Question

A box contains 12 balls some are red and some green. If 6 more red balls are put into the box, the probability of getting a red ball will be the double than earlier. Find number of each colour​

Answer 1

Answer:

solution

Given that

Total balls=12

Total balls=12Let the red balls be x

So,

$probability \: of \: red \: balls= no \: of \: red \: ball \div total \: no \: of \: balls$

$p 1\times \frac{x}{12}$

If the red balls increased to 6 then,

Total balls will be =12+6=18

Red balls will be=x+6

So,

P2 = x+6

$p2 = \frac{x + 6}{18}$

Now,

$\frac{x}{12} = \frac{x + 6}{18}$

$x = \frac{x + 6}{3}$

3x= x+6

2x=6

x=3

No. of red balls = 3+6=9

no. of green balls =12-3=9