Question

a box contains 13 bulbs out of ehich 5 bulbs are defective.3 bulbs are drawn one by one from the box without replacement. find the probability distribution of the number of defective bulbs drawn​

Answer 1

Step-by-step explanation:

Let X denote the number of defective bulbs in a sample of 3 bulbs drawn from a bag containing 13 bulbs. 5 bulbs in the bag turn out to be defective.

Then, X can take the values 0,1,2 and 3.

P(X=0)=P(No defective bulb )=13C35C0×8C3

=13×12×118×7×6

=14328

P(X=1)=P(One defective bulb)=13C35C1×8C2

=3×2×113×12×115×2×18×7

=14370

P(X=2)=P(Two defective bulb

Answer 2

Step-by-step explanation:

5/3

is probability of getting defeated bulb