a box contains 13 bulbs out of ehich 5 bulbs are defective.3 bulbs are drawn one by one from the box without replacement. find the probability distribution of the number of defective bulbs drawn
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Answered by
1
Step-by-step explanation:
Let X denote the number of defective bulbs in a sample of 3 bulbs drawn from a bag containing 13 bulbs. 5 bulbs in the bag turn out to be defective.
Then, X can take the values 0,1,2 and 3.
P(X=0)=P(No defective bulb )=13C35C0×8C3
=13×12×118×7×6
=14328
P(X=1)=P(One defective bulb)=13C35C1×8C2
=3×2×113×12×115×2×18×7
=14370
P(X=2)=P(Two defective bulb
Answered by
2
Step-by-step explanation:
5/3
is probability of getting defeated bulb
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