a box contains 15 red balls and 9 white balls and a ball is pulled at random find the probability of getting (a) red ball (b) white ball
Answers
Step-by-step explanation:
Answer
5
White
6
Red
9
Green
Total number of balls =5+6+9
=20
(i) Probability =
Total cases
favourable cases
P(Green) =
20
9
(ii) P(White or red) =
20
5+6
=
20
11
(iii) P(neither green nor white) = P(Red)
=
20
6
=
10
3
Answer:
(a) 5/8
(b) 3//8
Step-by-step explanation:
~~~~~~~~~~~~~~~~~~~~~~~~~~
{P = n(favourable event)/n(S)}
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
no.of balls in box = sample space (S)
S= 15+9 = 24
(a) red ball
~~~~~~~~~~~~~~~
favourable event = 15
P = 15/24
= 5/8
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(b) white ball
~~~~~~~~~~~~~~~~~~
favourable event = 9
P = 9/24
= 3/8
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hope it helps !!!