A box contains 15 tickets numbered 1, 2,.........15. Seven tickets are drawn at random one after the other with replacement. What is the probability that the drawn tickets do not have a number greater than 9?
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Probability of getting a number less than or equal to 9 is 3/5
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- We are given a box contains 15 numbered tickets from 1,2...15.
- We have to find out of 7 tickets,probability of not having a number greater than 9.
- So first, we calculate probability of getting a number greater than 9.
- We can get 10,11,12,13,14,15 i.e 6 numbers greater than 9.
- And P(getting one number from 1-15) :
= 1/15
- So P(getting a number greater than 9) :
= 6/15.
- Now we are drawing 7 such tickets,so total probability will be :
= (6/15)^7
= (2/5)^7
= 0.00169
- So the probability that the drawn tickets do not have a number greater than 9 is 0.00169.
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