Question

A box contains 19 balls bearing numbers 1,2,3,......,19 respectively. A ball is drawn

at random from the box. Find the probability that the number on the ball is (i) a

prime number (ii) an even number, (iii) a number divisible by 3, (iv) a number

divisible by 2 and 3
​

Answer 1

Answer:

Step-by-step explanation:

(i) 8/19 (ii) 8/19 (iii) 11/19 (iv) 9/19

Step-by-step explanation:

(i) Favourable outcomes = 2,3,5,7,11,13,17 and 19.

So, P(Prime Number) is 8/19

(ii) Favourable outcomes =

3,5,6,9,10,12,15 and 18.

So, P(Number divisible by 3 or 5) is 8/19

(iii) Favourable outcomes =

1,2,4,7,8,11,13,14,16,17 and 19.

So, P(Number neither divisible by 3 nor 5) is 11/19

(iv) Favourable outcomes =

2,4,6,8,10,12,14,16 and 18.

So, P(Even Number) is 9/19