Question

A box contains 2 apples, 3 mangoes, and 2 bananas. Two fruits are drawn at random. What is the probability that none of the fruits drawn is a banana

Answer 1

Answer:

5/7

Step-by-step explanation:

Total number of fruits in the box

= 2+ 3+ 2

= 7

probability that fruit is not a banana means fruits other than banana i.e apple and mangoes

therefore number of favourable outcomes (2+3=5) and total number of outcomes (7)

=5

7

Answer 2

Answer:

P=1/7

Step-by-step explanation:

Let us denote Apple=A,Mango=M and Banana=B

total fruits=2+3+2=7

Total ways =⁷C₂​=7!/2!*5!

=7*6*5!/1*2*5!

=42/2=21

Now possibility with none of bananas

AM, AA,MM,=3

P=3/21=1/7