A box contains 2 apples, 3 mangoes, and 2 bananas. Two fruits are drawn at random. What is the probability that none of the fruits drawn is a banana
Answers
Answered by
1
Answer:
5/7
Step-by-step explanation:
Total number of fruits in the box
= 2+ 3+ 2
= 7
probability that fruit is not a banana means fruits other than banana i.e apple and mangoes
therefore number of favourable outcomes (2+3=5) and total number of outcomes (7)
=5
7
Answered by
0
Answer:
P=1/7
Step-by-step explanation:
Let us denote Apple=A,Mango=M and Banana=B
total fruits=2+3+2=7
Total ways =⁷C₂=7!/2!*5!
=7*6*5!/1*2*5!
=42/2=21
Now possibility with none of bananas
AM, AA,MM,=3
P=3/21=1/7
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