Math, asked by archnakumarijorwal, 2 months ago

A box contains 2 red marbles, 3 green marbles, and 3 blue marbles.

If we choose a marble, then another marble without putting the first one back in the box, what is the probability that the first marble will be green and the second will be blue?

Answers

Answered by Anonymous
2

Answer:

This is simple,

So first we set this problem up

2 Red + 3 Blue + 7 Green = 12 Total Marbles

The formula for calculator probability is

# of favorable outcomes / # of possible outcomes

The number of favorable outcomes we have is 3 because we are trying to find the probability of pulling out a blue marble

The number of possible outcomes is 12 because we have 12 total marbles

3/12 simplifies to 1/4 which is .25

The probability of drawing a blue marble is 0.25 or 25%

Step-by-step explanation:

see also

We can assume the outcomes are equiprobable. That is, all the marbles have the same odds.

The rest is easy: when the outcomes are equiprobable, probability is calculated as the number of favorable outcomes divided by the number of possible outcomes.

Favorable outcomes: 3 blue marbles.

Possible outcomes (equiprobable): 12 marbles.

P = 3/12 = 1/4

The probability is 1/4 = 0.25

Also called 25%

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