A box contains 20 electric bulbs, out of which 4 are defective. Two bulbs are chosen at random from this box. The probability that at least one of these is defective, is:
a.4/19
b.7/19
c.12/19
d.21/95
Answers
Answered by
0
Answer:
Answer is a) 4/19
Hope it will correct.
Answered by
2
Answer:
7/19
Step-by-step explanation:
total no of out comes are=20c2
so atleast one defective means
4c1*16c1+4c2
P=(4c1*16c1+4c2)/20c2
7/9
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