A box contains 25 tickets numbered 1,2,3,...25 . If two tickets are drawn at random then the probability that the product of their number is even
Answers
Answer:
osba ajajjakajajajbwh
Step-by-step explanation:
njjwjwjjw we aa aa aa di
Answer:
We have,
Total number of tickets with numbers=25
Number of tickets with even numbers on them=12
Number of tickets with odd numbers on them=13
Number of tickets drawn=2
Now,
Selecting 2 tickets from the 25
Total number of possible choices= number of ways in which 2 tickets can be drawn from the total 25
So,
n=
25
C
2
=
2×1
25×24
=300
Product of two numbers would be even
If at least one of the numbers is even
So,
Number of ways in which 2 tickets with even numbers on both of them can be drawn + number of ways in which 2 tickets with an even number on one of them and an odd number an another can be drawn
m
A
=m
EA
1
+m
EA
2
=(
12
C
2
)+(
13
C
1
×
12
C
1
)
=
2×1
12×11
+
1
12
×
1
13
=(6×11)+(12×13)
=66+156
=222
Then,
Probability
P(A)=
n
m
A
=
300
222
=
50
37
Hence, this is the answer
Step-by-step explanation:
mark me as brain list