Question

A box contains 3 blue, 2 white and 4 red marbles. If a marble is drawn at random,
what is the probability that it will be
(a) White (b) Blue (c) Red (d) Green


answer fast pls

Answer 1

Answer:

(a) Total no. of marbles=3+2+4=9

(1) No. of white marbles=2

∴ probability of getting a white marble=

9

2

(2) No. of blue marbles=3

∴ probability of getting a blue marble=

9

3

=

3

1

(3) No. of red marbles=4

∴ probability of getting a red marble=

9

4

(b)Since, Total no. of balls = 5+8+7=20

(1) No. of balls that are white or green = 8+7=15

∴ probability of getting a white or green ball =

20

15

=

4

3

(2) No. of balls that are neither green nor red =7

∴ probability of getting a ball that are neither green nor red =

20

7

Answer 2

Hello,

Total number of marble = 3 + 2 + 4 = 9

(I) Probability to get white ball = 2 /9

(II) probability to get blue ball = 3/9 =1/3

(III) probability to get red ball = 4/9.

Hope it helps you

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