A box contains 3 blue and 2 red marbles while another box contains 2 blue
and 5 red marbles. A marble drawn at random from one of the boxes. Find the
probability that it is a blue marble.
Answers
Step-by-step explanation:
Total no. of marbles=3+2+4=9
(1) No. of white marbles=2
∴ probability of getting a white marble=
9
2
(2) No. of blue marbles=3
∴ probability of getting a blue marble=
9
3
=
3
1
(3) No. of red marbles=4
∴ probability of getting a red marble=
9
4
(b)Since, Total no. of balls = 5+8+7=20
(1) No. of balls that are white or green = 8+7=15
∴ probability of getting a white or green ball =
20
15
=
4
3
(2) No. of balls that are neither green nor red =7
∴ probability of getting a ball that are neither green nor red =
20
7
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Answer:
total no. of marbles of box A = 5
Propability of blue marble in A = 3/5
Total no.of marbles of box B = 7
Probability of blue marbles in box B = 2/7
Most probability = 3/5 * 2/7
= 6/35
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