Question

A Box contains 3 blue balls and 5 yellow ball's. A sample of 3 balls is selected from the box without replacement.Let M be the number of blue balls contained in the sample then find the probability distribution for M.​

Answer 1

Answer:

Correct option is

C

3

1

,

5

3

A box contains 6 green balls, 4 blue balls, 5 yellow balls.

Total number of balls n(S)=6+4+5=15

(a)

Let A be the probability of getting yellow ball.

n(A)=5

Thus the probability of getting yellow ball is P(A)=

n(S)

n(A)

=

15

5

=

3

1

.

(b)

Let B be the probability of not getting green ball. That is, probability of getting blue and yellow balls.

n(B)=4+5=9

Thus the probability of getting yellow ball is P(B)=

n(S)

n(B)

=

15

9

=

5

3

.