Question

A box contains 3 defective mangoes and 21 good mangoes. One mango is drawn from the box at random. Find the probability of getting

a defective mango

a good mango

Answer 1

Answer:

a defective mango : 3/21 or 1/7

a good mango : 18/21 or 6/7

Step-by-step explanation:

we can find the probability by doing this :

1 find the total number likewise here we need to find out good mangoes first so we can subtract the given number from the total .

2 then we need to form a fraction out of it and convert it to the lowest or standard form .

i hope this helps you

Answer 2

Answer:

Defective mango = 1/8

Good mango = 7/8

Step-by-step explanation:

There are 3 defective and 21 good mangoes. So, total mangoes are 21 + 3 => 24 mangoes.

Probability = (Favourable outcomes)/(Total outcomes)

So, probability of getting a defective mango = 3/24 => 1/8

∴ Probability of getting a good mango = 21/24 => 7/8

OR

Probability of getting a good mango = 1 - 1/3 => 7/8