Question

A box contains 3 defective mangoes and 21 good mangoes. One mango is drawn.
from the box at random. Find the probability of getting
(i) a defective mango
(ii) a good mango.​

Answer 1

Step-by-step explanation:

Good mangoes= 21

defective=3

Total mangoes =24

probability=

1) defective mangoes= 3/24=1/8

2) good mangoes=21/28=7/8

Answer 2

Answer:

Your answer is...

Step-by-step explanation:

probability of getting a defective mango ==

defective mangoes÷total mangoes

==

3/21+3=3/24=1/8

answer is 1/8

probability of good mangoes==

good mangoes÷total mangoes

==

21/24=7/8

probability of good mangoes = 7/8