Question

A box contains 3 red, 2 blue and 5 green marbles. A marble is drawn at random. What is

the probability of getting

a) A red marble

b) A blue marble

c) A green marble​

Answer 1

Answer:

a) A red marble probability is 3/10

b) A blue marble probability is 1/5

c)A green marble probability is 1/2

Answer 2

☆QUESTION☆

A BAG CONTAIN 3 RED BALLS,2 BLUE AND 5GREEN MARBLES.A MARBLE IS DRAWN AT RANDOM.WHAT IS THE PROBABILITY OF GETTING.......A)RED B)BLUE C)A GREEN MARBLE

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☆ANSWER☆

$<font color =orange >$

A) RED MARBLES....

TOTAL OUTCOME=3+2+5= ((10))

a) P(getting) red marbles=3

$\frac{total \: no. \: of \: outcomes}{favaurable \: outcome}$

$\frac{3}{10} = red \:marbles$

$<font color =blue >$

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B) A BLUE MARBLES...

TOTAL OUCOMES=10

b)P(getting)blue marbles=2

$\frac{total \: no. \: of \: outcomes}{favaurable \:outcomes}$

$\frac{2}{10}$

$\frac{1}{5} = blue \: marbles$

$<font color =green >$

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C)A GREEN MARBLES

TOTAL OUTCOMES=10

c) P(getting)green marbles=5

$\frac{total \: no. \: of \: outcomes}{favaurable \: outcomes}$

$\frac{5}{10}$

$\frac{1}{</u><u>5</u><u>} =green \: marbles$

____________________________

$\mathcal \red{red \: marbles = \frac{3}{10}}$

$\mathtt \blue{blue \: marbles = \frac{1}{</u><u>5</u><u>}}$

$\mathsf \green{green \: marbles = \frac{1}{</u><u>5</u><u>}}$

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