Question

a box contains 3 red,4 black and 5 green balls the number of ways in which 3 can be selected from the box if at least one red ball is to be included is

Answer 1

Answer: there are 6 ways

Step-by-step explanation:

we need atleast 1 red ball therefore there would be 3 cases ;

1) when 1 red ball is included = RBG, RBB, RGG = 3 .........here arrangement is not seen

2) when 2 red balls included : RRB, RRG = 2

3) when 3 red included : RRR = 1

total ways = 3 + 2 + 1 = 6 ways