Question

A box contains 3 red apples and 4 green apples. If one apple is selected at random from the box, what is the probability that it is green​

Answer 1

Answer:

4/7

Step-by-step explanation:

Total apples=3+4=7

Red apples=3

Green apples=4

Probability of getting green apple=4/7

Answer 2

Answer:

${ \large{ \boxed{ \pink{ \bf \: Probability = \frac{4}{7} }}}}$

Step-by-step explanation:

Given :-

A box contains 3 red apples and 4 green apples. If one apple is selected at random from the box,

To Find :-

Probability of green

Solution :-

We know thta

Probability = Favourable outcome/Total outcome

Probability = 4/(3 + 4)

Probability = 4/7

Thus,

Probability is 4/7