Question

A box contains 3 red balls, 5 yellow balls and 6 black balls. What is the probability of getting a red ball, if a ball is selected at random?

Answer 1

Given

A box contains 3 red balls, 5 yellow balls and 6 black balls.

To find

What is the probability of getting a red ball, if a ball is selected at random?

Solution

• Number of red balls = 3
• Number of yellow balls = 5
• Number of black balls = 6

★ Total number balls = 3 + 5 + 6 = 14

$\sf P(E)=\dfrac{Number\:of\:favourable\:outcomes}{total\:number\:of\:outcomes}$

Let E be the event of getting red balls

∴ P(getting red balls) = 3/14

Extra Information

• P(E) = 0 {E is an impossible event}
• P(E) = 1 {E is a sure event}

Answer 2

✯✯ QUESTION ✯✯

A box contains 3 red balls, 5 yellow balls and 6 black balls. What is the probability of getting a red ball, if a ball is selected at random?

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✰✰ ANSWER ✰✰

$\longmapsto\tt{No.\:of\:Red\:balls=3}$

$\longmapsto\tt{No.\:of\:yellow\:balls=5}$

$\longmapsto\tt{No\:of\:Black\:balls=6}$

$\longmapsto\tt{Total\:Balls=3+5+6}$

$\longmapsto\tt{14}$

➮Probability of getting a red ball : -

$Probability=\dfrac{No.\:of\:fav.\:Outcomes}{Total\:no.\:of\:Outcomes}$

$\red\longmapsto\:\large\underline{\boxed{\bf\green{Probability}\orange{=}\purple{\dfrac{3}</p><p>{14}}}}$

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★Probability : -

It is the chances of happening or occuring of an event..

OR

It is the possibility of an event to occur before its actual occurance..

★Probabilty of an event lies between 0 and 1..

★Probability of impossible event is 0..

★Probability of possible event is 1.

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