A box contains 3 red marbles 6 white marbles and 7 green marbles. one marble is taken out of the box at random. What is the probability that the marble taken out will be (1) red marble (2 ) white marble ( 3) not green ?
Answers
Step-by-step explanation:
total number of marbles is 16
1) no. of red marbles Is 3
so the P = 3/16
2) no. of white marbles is. 6
so the P = 6/16
3) no. of red marbles + no.of white marbles = 3+6 = 9
so the P = 9/16
Answer:
1.3/16 2.6/16 3.9/16
EXPLANATION:
IN TOTAL THERE ARE 16 MARBLES AND
THEREFORE ...
IF YOU TAKE OUT ONE MARBLE AT RANDOM THEN THE PROBABILITY OF THE MARBLE BEING RED WILL BE= (no. of red marbles) /total no.
= 3/16
similarly....PROBABILITY OF GETTING WHITE MARBLES
WILL BE....6/16....which if you round up...will be 3/8
and then it's said..the probability of not getting a green marble....
Now we know that all the probabilities of the every event sum up to 1
therefore the probability of not getting a green marble will be (1-PROBABILITY OF GETTING GREEN MARBLE)
THEREFORE...1-7/16....THAT IS EQUAL TO 9/16
..I HOPE..YOU ARE SATISFIED WITH THE EXPLANATION...