Question

A box contains 3 yellow, 2 red, 4 green and 3 black marbles.
Two marbles are taken one after the other at random from
the box. What is the probability that both marbles are red?
(d) 2/57
(c) 1/66
(a) 1/50
(b) 1/60​

Answer 1

Given info : A box contains 3 yellow 2 red, 4 green and 3 black marbles. Two marbles are taken one after the other at random from the box.

To find : the probability that both marbles are red.

Solution : here no of red marbles = 2

no of yellow marbles = 3

no of green marbles = 4

no of black marbles = 3

So Total no of marbles = 2 + 3 + 4 + 3 = 12

Total possible events , n(s) = ¹²C₂ = 12!/10!2! = 12 × 11/2 = 66

favourable events , n(E) = ²C₂ = 2!/0!2! =

so, probability = n(E)/n(S) = 1/66

Therefore the probability that both marbles are red is 1/66. i.e., option (c)

Answer 2

Answer:

1/66 is theanswer

Step-by-step explanation:

12×11÷2 = 66