Question

A box contains 30 cards with the numbers 1 to 30.

One card is drawn from this box.

What is the probability that number on the card is:-

(i) perfect cube,
(ii) divisible by 4,
(iii) divisible by both 2 and 3.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

n(S)={1,2,3..30}=30

let A be the event of drawing a perfect cube

n(A)={1,8,27}=3

p(A)=n(A)/n(S)=3/30=1/10

let B be the event of drawing a number divisible by 4

n(B)={4,8,12,16,20,24,28}=7

p(B)=n(B)/n(S)=7/30

Let C be the event of drawing a number divisible by both 2 and 3

n(C)={2,3,4,6,8,9,10,12,14,15..30}=20

p(C)=n(C)/n(S)=20/30=2/3

Hope it helps