Math, asked by shastrived, 5 months ago

a box contains 30 numbered card from 1 to 30 three cards are drawn at random then find the probability that their median is 10​

Answers

Answered by THEGOODBOY90
13

Answer:

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Answered by darshilx
2

Answer:

9/203

Step-by-step explanation:

probability = \frac{Number of Favourable Outcomes}{Number of Total Outcomes}

Number of Favourable Outcomes: we want median to be 10, and we have numbers from 1 to 30. So we must have 10 in all combinations of 3 numbers. For the rest of 2 numbers we will take combinations from 9 numbers before 10 and 20 numbers after 10. so the number of favourable outcomes would be 9×20.

Number Of Total Outcomes =  _{30}c_{3}

so the probability would be = \frac{9 * 20}{30C3} = \frac{9}{203}

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