Question

a box contains 30 tickets bearing only one number from 1 to 30 on each .if one ticket is drawn at random.findthe propabability of an even that the ticket drawn beavs i.an odd number ii.a complete square number.​

Answer 1

Answer:

i) 0.5

ii)1/6

Step-by-step explanation:

When Odd number ==favorable condition

Sample space includes {1,3,5,7,9,11,13,15,17,19,21,23,25,27,29}

P(getting odd number) = $\frac{15}{30} =0.5$

When complete square number ==favorable condition

Sample space includes {1,4,9,16,25}

P(getting a complete square) = $\\\tt \frac{5}{30} =\frac{1}{6}$