A box contains 36 tickets numbered 1 to 36, 1 ticket drawn at random. Find the probability that the number on the ticket is either divisible by 3 or is a perfect square .
Answers
Answered by
5
Answer:3 is u ans
Step-by-step explanation: no are 3 6 9 12 15 18 21 24 27 30 33 and 36 = tatal 12 12%36=3
zendax:
probability always lie between 0 to 1...so your answer is wrong
forry its 1/3 iam a stuid
12/36 is 1/3 sorry for mistake
i.r 0.33333
answer will be 4/9
ooo i mis perfectv qube one
Answered by
10
Total number of tickets that are divisible by 3 = 12 i.e (36/3)
Total number which are perfect square = 6 i.e (1,4,9,16,25,36)
Common multiple = 2 i.e(9 and 36)
So total number of possible events= 12+6-2= 16
So the probability =16/36= 4/9
Similar questions