A box contains 36 tickets numbered from 1to 36.one ticket is drawn at random.find the probaility that the number on the ticket is either divisible by 3 or a prefect square
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Answer:
4/9
Step-by-step explanation:
Numbers divisible by three between 1-36= 3, 6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36
=12 numbers
Perfect squares between 1-36- 1, 4, 9, 16, 25, 36
=6-2 (Since 9 and 36 are repeated)
=4 numbers
Therefore, the probability of picking a ticket with the number of he given conditions = 12+4/36
=16/36
=4/9
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