Question

A box contains 4 bad and 6 good tubes. Two are drawn out together at random.

Find the probability that (1) the second one is also good given that first one is good

(ii) both are bad.​

Answer 1

Answer:

1)frist tube and second tube both are good=2

total no. of tube=10

$1). \frac{2}{10} = \frac{1}{5}$

2)2 bad tube=2

total tube =10

$\frac{2}{10} = \frac{1}{5}$