Question

A box contains 4 blue and 5 green balls. Four balls are drawn randomly and replaced. What is the probability that two blue and two green balls are drawn?

Answer 1

Answer:

$\frac{4}{9}$

Step-by-step explanation:

Number of favourable outcomes = 2 + 2 = 4

Number of possible outcomes = 4 + 5 = 9

P(E) =

$\frac{number \: of \: favourable \: outcomes}{total \: number \: of \: possible \: outcomes}$

=>

$\frac{4}{9}$