Math, asked by yuvasaiyuvasai9958, 1 year ago

A box contains 4 red 5 blue and 6 green balls,3 balls are drwan aymt random probabi of different cvolours

Answers

Answered by chandanamothukuru

0

(4c1*5c1*5c1)/15c3 = 24/91

Answered by Anonymous

0

Answer:

Step-by-step explanation:

Total balls=4+5+6=15

Ways of selecting 3 balls of different colours=

(4C1*5C1*6C1)/15C3=24/91,

hope you understood

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