Math, asked by sawantvnk, 4 days ago

A box contains 4 red, 6 blue, 5 green pens. What is the probability that the pen picked up

is :

a) Blue b) Red c) Not blue​

Answers

Answered by johanjomykuru
1

Answer:

a, 0.4 ( 6/15 )

b, 0.26 ( 4/15 )

c, 0.6 ( 3/5 )

Step-by-step explanation:

Total number of balls = 4 + 6 + 5 = 15

Probability of getting a blue ball = Number of blue balls / Total number of balls

A, Probability of getting a blue ball = 6 / 15 = 0.4

Probability of getting a red ball = Number of red balls / Total number of balls

B, Probability of getting a blue ball = 4 / 15 = 0.26

Probability of getting a blue ball = ( Number of blue green + Number of red balls) / Total number of balls

C, Probability of getting a blue ball = 9 / 15 = 3 / 5 = 0.6

Answered by emilyjayajoshua
0

Step-by-step explanation:

let S be the sample space.

S={R1,R2,R3,R4,B1, B2,B3,B4,B5,B6,G1,G2,G3,G4,G5}

n(S)=15

let A be the event of getting the pen picked up is blue.

A={B1, B2,B3,B4,B5,B6}

n(A)=6

n(P)=n(A)/n(S)

=6/15

=2/5

let B be the event of getting the pen picked up is red

B={R1,R2,R3,R4}

n(B)=4

n(P)=n(B)/n(S)

=4/15

let C be the event of getting the pen picked up is not blue.

C={R1,R2,R3,R4,G1,G2,G3,G4,G5}

n(C)=9

n(P)=n(C)/n(S)

=9/15

=3/5

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