Question

A box contains 4 red balls,5 green balls, P white balls.If the probability of randomly picked a ball from the box to be red ball 1/3 then find the number of white balls​

Answer 1

Answer:

No.Of red = 4

no.Of green=5

white =p

p(red) =1/3

4*3=12

white=red+green = 12

= 4 + 5 = 12

= 9 = 12

white =12-9

white = 3

…. No. Of white=3

Answer 2

The number of white balls is 3.

Given,

A box contains:

4 red balls,

5 green balls, and

P white balls.

The probability that a randomly picked ball is red, is 1/3.

To find,

The number of white balls​.

Solution,

It is given here that a box is having 4 red balls, 5 green balls, and P white balls. And, the probability of picking a red ball randomly is 1/3.

Now, the probability is defined as the ratio of the number of favorable outcomes to the number of total outcomes for an event.

Here, the total number of outcomes will be the total number of balls that is,

4 + 5 + P

= (9 + P)

To determine the probability of picking a red ball, the favorable outcome will be the number of red balls that is, 4.

The probability that the ball picked is red, is given to be $\frac{1}{3} .$

So, probability,

$P(picking \hspace{3} a \hspace{3} red\hspace{3} ball)=\frac{1}{3} =\frac{favorable \hspace{3} outcomes \hspace{3} (4)}{total \hspace{3} outcomes \hspace{3}(9+P)}$

$\implies \frac{1}{3} =\frac{4}{9+P}$

Simplifying,

$9+P=12$

$\implies P=3$.

Therefore, the number of white balls is 3.

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