Question

A box contains 4 white balls and 3 red

balls. In succession, two balls are

randomly selected and removed from

the box. Given that the first removed

ball is white, the probability that the

second removed ball is red is​

Answer 1

Answer:

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Step-by-step explanation:

Required probability would be,

P (B/A) = Probability of drawing a red ball in the second draw given that a white ball has already been drawn in the first draw.

Since 6 balls are left after drawing a white ball in the first draw and out of these 6 balls 3 are red, so

P(B/A) = 3/6 = 1/2.