A box contains 40 red balls and 60 black balls. from the box balls are drawn one by one at random without replacement till all the balls are drawn.the probability that the last ball drawn is black is ?
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total number of event=60+40=100
ATQ
Probability of black=60/100
=3/5ans
ATQ
Probability of black=60/100
=3/5ans
Answered by
1
THE TOTAL NUMBER OF BALLS ARE
SUM OF RED BALL +SUM OF BLACK BALLS
=60+40=100
THEREFORE THE P(e) OF BLACK BALLS IS 60/100
=3/5
SUM OF RED BALL +SUM OF BLACK BALLS
=60+40=100
THEREFORE THE P(e) OF BLACK BALLS IS 60/100
=3/5
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