A box contains 5 black ,7 red and 6 green balls three balls are drawn from this box one after the other without replacement what is the probability that the three balls are
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Two green balls can be selected 5*4÷2=10 different ways, 2 black balls can be selected 3*2÷2=3 different ways, and 2 red balls can be selected 7*6÷2=21 different ways, total of 10+3+21=34 ways to select 2 balls of same color.
There are 5+3+7=15 balls present. As 2 balls regardless of their color can be selected 15*14÷2=105 different ways, probability of drawing 2 balls of same color is 34105
Answer : 34105
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