Math, asked by Goldy108, 11 months ago

A box contains 5 defective and 10 non-defective lamps. 8 lamps are drawn at random in succession without replacement. What is the probability that the 8 lamp is the 5 defective?

Answers

Answered by rakshitha33399
1

Answer:

8/429

Step-by-step explanation:

5 defective lamps can be selected at 5c5 ways

and

3 non defective should be selected from 10 non defective lamps as we want total 8 lamps

so

5c5 ×10c3/15c8 = 8/429

(5c5=1,10c3=120,15c8=6435)

Answered by amitnrw
8

Probability = 8/429 of 5 Lamps Defective out of 8 Selected Lamps from a box containing 5 defective & 10 non-defective lamps

Step-by-step explanation:

A box contains 5 defective and 10 non-defective lamps

Total = 15 Lamps

8 Lamps are Selected

8 Lamps out of 15 can be selected in ¹⁵C₈   ways = 6435 Ways

Out of 8

5 Lamps are defective  - 5 Lamps can be selected in ⁵C₅ = 1 Ways

3 Laps Can be selected from 10 Defectives in ¹⁰C₃  = 120 Ways

Probability = 120/6435  = 8/429

Probability = 8/429 of 5 Lamps Defective out of 8 Selected Lamps from a box containing 5 defective & 10 non-defective lamps

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