Question

A box contains 5 green, 4 yellow and 3 white balls. Three balls are drawn at random. What is the probability that they are not of same colour

Answer 1

Answer:

Step-by-step explanation:

Total no. of balls : 12

Let balls are GGGGG, YYYY and WWW.

So, we could solve this question in 2 different ways:

The question can be solve by consedring the two senarios:

1) We can calculate the things that we want in above case senarios is not the same colour.

2. The things we don't want. In this senario we can calculate the answer (1 - we don't want ).

So, the scenarios we don't want are:

Probability of Getting a Green ball from the box = (5/12) * (4/11) * (3/10) = 60/1320

Probability of Getting Yellow ball = (4/12) * (3/11) * (2/10) = 24/1320

Probability of Getting White Ball = (3/12) * (2/11) * (1/10) = 6 /1320

So, Probability of getting Green or Yellow or White ball = (60/1320) + (24/1320) + (6/1320) = 9/132 = 3/44.

 

**"Not of the same colour" means that "not all 3 can be the same colour". So, you need to take into account the scenarios in which you have 2 of 1 colour and 1 of a second colour.

Hope it helps!!!!!!

Please mark my answer as brainliest dear!!!!!

Answer 2

Let's find the probability that three drawn marble are of the same color and subtract that from 1.

P(three marbles are NOT of the same color) = 1 - P(three marbles are of the same color) =

= 1- (P(all three are green) + P(all three are yellow) + P(all three are white)) =