Question

A box contains 5 green, 8 yellow and 7 brown balls. One ball is taken out from a box at random. What is the probability that the ball taken out is (i) yellow ? (i) brown ? (ii) neither green nor brown ? (iv) not brown ?

Answer 1

Green = 5

Yellow = 8

Brown = 7

Total number of balls = 5 + 8 + 7 = 20

.

P(yellow) = 8/20 = 2/5

P(brown) = 7/20

.

Neither green nor brown = 20 - 5 - 7 = 8

P(Neither green nor brown) = 8/20

.

Not brown = 20 - 7 = 13

P(not brown) = 13/20

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