Question

A box contains 5 green marbles, 8 red marbles and 7white marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be(i)red?(ii) white?(iii)not green?

Answer 1

Answer:

(i) red = 8/20 = 2/5.

(ii) white = 7/20.

(iii) not green = 15/20 = 3/4.

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Answer 2

Step-by-step explanation:

Number of green marbles = 5

Number of red marbles = 8

Number of white marbles = 7

Total number of balls = 20

generally,

$probability \: of \: an \: event = \frac{number \: of \: favourable \: outcome}{total \: number \: of \: outcomes}$

applying this:

i) P ( marble taken out is red) =

Number of red marbles / Total number of marbles

= 8/20

= 2/5

ii) P ( marble taken out is white) =

Number of white marbles / Total number of marbles

= 7/20

iii) P ( marble taken out is not green) =

Number of white + red marbles / Total number of marbles

= (8+7) / 20

= 15/20

= 3/4