Question

A box contains 5 red, 8 blue and 3 green pens. Rujuta wants to pick a pen at random. What is the probability that the pen is blue?​

Answer 1

Answer:

Total number of pens =5+8+3

=16

Number of blue pens =8

Therefore, required probability =

Total number of pens

Number of blue pens

=

16

8

=

2

1

Hence, the probability that the pen is blue is =

2

1

Answer 2

Answer:

$\frac{1}{16}$

Step-by-step explanation:

Total number of pens = 5+8+3 = 16

Number of blue pens =8

Therefore, required probability =

$\frac{number \: of \: blue \: pen}{total \: number \: of \: pen} \: = \frac{8}{16}$

2

--

1

Hence, the probability that the pen is blue

$\frac{2}{1}$