Math, asked by kevin2139, 1 year ago

a box contains 5 red 8 green and 7 blue balls one ball is drawn at random what is the probability that the drawn ball is non red

Answers

Answered by llHarmanherell
1

P(non red)=

 \frac{no. \: of \: favourable \: outcomes}{total \: outcomes}  =  \frac{15}{20}  =  \frac{3}{4}

Answered by pulakmath007
0

The probability that the drawn ball is non red = 3/4

Given :

  • A box contains 5 red , 8 green and 7 blue balls

  • one ball is drawn at random

To find :

The probability that the drawn ball is non red

Solution :

Step 1 of 3 :

Find total number of possible outcomes

The box contains 5 red , 8 green and 7 blue balls

Total number of balls

= 5 + 8 + 7

= 20

So total number of possible outcomes = 20

Step 2 of 3 :

Find total number of possible outcomes for the event

Let A be the event that the drawn ball is non red

Total number of non red balls

= 8 + 7

= 15

So total number of possible outcomes for the event A is 15

Step 3 of 3 :

Find the probability

Hence the required probability

= P(A)

\displaystyle \sf{  =  \frac{Number \:  of  \: favourable \:  cases \:  to \:  the \:  event \:  A }{Total \:  number  \: of \:  possible \:  outcomes }}

 \displaystyle \sf{ =  \frac{15}{20} }

 \displaystyle \sf{ =  \frac{3}{4} }

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