Question

A box contains 5 red marbles, 8 white marbles and 4 green marbles a box contains 5 red marbles 8 white marble and 4 green marble .One marble taken out of the box at random. what is the probability that the marble taken out. will be(1) red ? (2) white? (3)not green?. ​

Answer 1

SOLUTION :-

=> (1) The probability of the getting a red marbles = Number of red marble / Total number of marbles.

=> The probability of the getting a red marbles = 5/(5+8+4)

=> 5/17.

=> (2) The probability of the getting a white marbles = Number of white marble / Total number of marbles.

=> The probability of the getting a white marbles = 8/(5+8+4)

=> 8/17.

=> (3) The probability of the getting a green marbles = Number of green marble / Total number of marbles.

=> The probability of the getting a green marbles = 4/(5+8+4)

=> 4/17.

=> p(a green marbles) + p( not a green marbles) = 1.

=> p( a not green marbles) = 1 - p(a green marbles)

=> p( a not green marbles) = 1 - 4/17

=> p( a not green marbles) = 13/17.

Thus, the probability of not getting a green marbles is 13/17.

Answer 2

No. of red marbles = 5

No. of white marbles = 8

No. of green marbles = 4

Total no. of marbles = 17

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(i) Probability of getting a red marble = $\large\sf\frac{5}{17}$

(ii) Probability of getting a white marble = $\large\sf\frac{8}{17}$

(iii) Probability of getting a green marble = $\large\sf\frac{4}{17}$

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Probability of not getting a green marble

= 1 - P(E)

= $\large\sf{1-\frac{4}{17}}$

= $\large\sf\frac{13}{17}$