Question

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be
(i) red?
(ii) white?
(iii) not green?
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Answer 1

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The Total no. of marbles= 5 + 8 + 4 = 17

P(E) = (Number of favourable outcomes/ Total number of outcomes)

(i) Total number of red marbles= 5

P (red marbles) = 5/17 = 0.29

(ii) Total number of white marbles= 8

P (white marbles) = 8/17 = 0.47

(iii) Total number of green marbles = 4

P (green marbles) = 4/17 = 0.23

∴ P (not green) = 1 – P (green marbles) = 1 – (4/17) = 0.77

Answer 2

ANSWER ::

Total number of balls in the bag = 5 +8+4 = 17

So the total number of possible outcomes = 17

(i) Let A be the event that the ball is RED

So the total number of possible outcomes for the event A is 5

So the required probability that the ball is RED is =P(A) = 5/17

(ii) Let B be the event that the ball is WHITE

So the total number of possible outcomes for the event B is 8

So the required probability that the ball is WHITE is =P(B) = 8/17

(i) Let G be the event that the ball IS GREEN

So the total number of possible outcomes for the event G is 4

So the probability that the ball is GREEN is =P(G) = 4/17

So the required probability that the ball is NOT GREEN is = 1-4/17 = 13/17

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