A box contains 5 red marbles 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What
is the probability that the marble taken out will be (1) red ? (2) not green ?
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Correct Question:
- A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red ? (ii) white ? (iii) not green?
Required Solution:
Total no. of marbles in the box = 5 + 8 + 4
Total no. of marbles in the box = 5 + 12
Total number of marbles in the box = 17
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(i) Probability (Red) = Number of red marbles/Total number of marbles
- Probability (Red) = 15/17
(ii) Probability (White) = Number of white marbles/Total number of marbles
- Probability (White) = 8/17
(iii) Probability (Green) = Number of green marbles/Total number of marbles
- Probability (Green) = 4/17
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- Probability (Not Green) = 1 - Probability (Green)
Probability (Not Green) = 1 - 4/17
Probability (Not Green) = 13/17
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