Math, asked by saigandla12345, 3 months ago

A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken
out of the box at random. What is the probability that the marble taken out will be (1) red?
(ü) white ? (iii) not green?

Answers

Answered by nidhimakani092

Answer:

1st) 5/17

2nd) 8/17

3rd) 13/17

Answered by Anonymous

Total possible outcome = 5+8+4

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:$ => 17 marbles

$\\$

(i)

No. of possible outcome = 5

$\\$

:. Probability of red marble

= $\frac{No.\: of \:possible\: outcome}{Total\:possible\:outcome}\\$

=> $\frac{5}{17}\\$

$\\$

(ii)

No. of possible outcome = 8

$\\$

:. Probability of white marble

= $\frac{No.\: of \:possible\: outcome}{Total\:possible\:outcome}\\$

=> $\frac{8}{17}\\$

$\\$

(iii)

No. of possible outcome = (5+8) => 13

$\\$

:. Probability of not green marble

= $\frac{No.\: of \:possible\: outcome}{Total\:possible\:outcome}\\$

=> $\frac{13}{17}\\$

$\\\\$

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