Question

. A box contains
5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be1) red, 2)white, 3)not green
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Answer 1

Answer:

1.1/5

2.1/8

3.1/13

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Answer 2

Answer:

Question

✳️A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be1) red, 2)white, 3)not green

Solution ⬇️

✍️S={5+8+4}={17}

✍️n(S)=17

• Let A be the event of getting red marble

✍️A={5}

✍️n(A)=5

$p(a) = \frac{n(a)}{n(s)} = \frac{5}{17}$

• Let B be the event of getting white marble

✍️B={8}

✍️n(B)=8

$p(b) = \frac{n(b)}{n(s)} = \frac{8}{17}$

• Let C be the event of getting not green

✍️C={red + white}={5+8}={13}

✍️n(c)=13

$p(c) = \frac{n(c)}{n(s)} = \frac{13}{17}$

Step-by-step explanation:

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