Question

A box contains 6 bad and 4 good apples. Two are chosen from the box out at a time. One of them is tested and found to be good. What is the probability that the other one is also good?

Answer 1

Hi dude....

HERE IS UR ANSWER.....

Let A= one of the apple drawn is good and

B=The other apple is good .

P(A∩B) =P(both apples drawn are good)

6C210C2=13

knowing that one apple is good,the conditional probability that the other apple is also good is required i.e P(B/A)is required.

P(B/A)=P(A∩B)P(A)

1/3/6/10 =5/9

HOPE THIS HELPS....

@HARSHA.. ✌

Answer 2

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Let A= one of the apple drawn is good and

B=The other apple is good .

P(A∩B) =P(both apples drawn are good)

6C210C2=13

knowing that one apple is good,the conditional probability that the other apple is also good is required i.e P(B/A)is required.

P(B/A)=P(A∩B)P(A)

1/3/6/10 =5/9

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