A box contains 6 red balls and 4 green balls. Four balls are selected at random. What is the probability that two of the selected balls will be red and two will be green
Answers
Answered by
1
Answer:
2/5
Explanation:
number of red balls=6
number of green balls=4
total number of balls=10
probability of getting selected balls
=number of selected balls/total nOK of balls
=4/10
2/5 ans.
Answered by
0
Answer:
3/7
Explanation:
red balls = 6
green balls = 4
What is the probability that two of the selected balls will be red and two will be green?
4 balls from 10 balls = 10C4 = 210
2 red balls from 6 balls = 6C2 ways = 15.
2 green balls from 4 green balls = 4C2 ways = 6.
Total balls = 6 red + 4 green = 10
Probability that two selected balls will be red and two will be green:
Since red and green ball is asked, we have multiplied
(15 * 6) = 90.
90/210 = 3/7
Similar questions