Question

A box contains 6 red beads and 5 white beads. Another box contains 8 red beads and 4 white beads. If one beads is taken from each box, then: (a) what is the number of possible pairs? (b) what is the probability of both beads being red? (c) what is the probability that both beads are white? (d) what is the probability of getting at least one red bead?​

Answer 1

Answer:

First box contains 8 black and 12 white beads Second box contains 9 black and 6 white beads.

(a) One black bead from each box is taken.

Number of such cases = 8×9=72

Total number of possibilities = 20×15=300

Probablity of getting both black beads =

300

72

=

25

6

(b) One black and one white bead is taken.

So if one black bead is taken from first box then one white bead is taken from second box and if one white bead is taken from first box then one black bead is taken from second box.

Number of such cases = 8×6+12×9=48+108=156

Total number of possibilities = 20×15=300

Probablity of getting one black and one white bead =

300

156

=

25

13

Answer 2

Answer:

super and this is super one application