Question

A box contains 6 red pens, 9blue pens and 3 black pens. A pen is selected at random from the box. Find the probability of that the pen is :(a) green(b)not green (c) black(d)not black

Answer 1

Step-by-step explanation:

( a )there are no green pens so the probability will be zero in the first case

( b ) the probability will be 1 bcoz there are no green pens so we have to remove pens that are not green

( c )blackpens =3=c(n) …(1)

s(n)=18

p(c)=c(n)/s(n)

p(c)=3/18

p(c)=1/6

(d) not black =d(n)=15

p(d)=to 15/18

p(d)= 5/6