Question

A box contains 6Red beads and 5white beads another contains 8red beads and 4white beads If one bead is taken from each box , Then a, Both are different. b, At least one red bead. c, At least one white bead

Answer 1

Step-by-step explanation:

box 1: 6 Red, 5White

box 2: 8Red, 4 White

P(R1) = Red from box1 =6/11

p(W1)= White from box1 = 5/11

p(R2) = Red from box2 =8/12=2/3

p(W2) = White from box2 = 4/12 =1/3

A) Both different

p(R1)×p(w2) + p(R2)×p(w1)

=6/11×1/3 + 5/11×2/3 = 6+10/33=16/33

B) at least one red

It can be 2 ways.

i) both different as above = 16/33 or

ii) both red

=p(R1)×p(R2)

=6/11×2/3=12/33

16/33 +12/33= 28/33

C) at least one white

can be 2 ways

i) both different = 16/33

ii)both white = p(W1)×p(W2) =5/11×1/3 = 5/33

16/33+5/33=21/33=7/11