Question

a box contains 70 bolts and 120 nuts . on checking the box , it was found that half of the bolts and one fourth of the nuts are rusted . if one of them are choosen at random find the probability that it is rusted
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Answer 1

Answer:

Total number of nuts and bolts in the box = 150 + 50

= 200

Number of nuts and bolts rusted = 1/2 × 200 = 100

P(a rusted nut or bolt) = 100/100 = 1/2

Answer 2

Step-by-step explanation:

Total no. of things in box=bolts +nuts=70+130=200

half of them are rusted , so no. of rusted nuts and bolts=200/2=100.

propability=no.of rusted nuts and bolts/total no. of nuts and bolts=100/200=1/2.

Therefore , propability that it is rusted =1/2 or 0.5.

hope it will help you :)